125x^1/3-25x^-2/3

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Solution for 125x^1/3-25x^-2/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(125*x^1)/3-((25*x^-2)/3) = 0

(125*x)/3+(-25/3)*x^-2 = 0

125/3*x-25/3*x^-2 = 0

25/3*x*(5-x^-3) = 0

-1*x^-3 = -5 // : -1

x^-3 = 5

-3 < 0

1/(x^3) = 5 // * x^3

1 = 5*x^3 // : 5

1/5 = x^3

x^3 = 1/5 // ^ 1/3

x = (1/5)^(1/3)

(25*x)/3 = 0

25/3*x = 0 // : 25/3

x = 0

x in { 0} 

x = (1/5)^(1/3)

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